1/x^3+29/x=4/x^2

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Solution for 1/x^3+29/x=4/x^2 equation: 


D( x )

x^3 = 0

x = 0

x^2 = 0

x^3 = 0

x^3 = 0

1*x^3 = 0 // : 1

x^3 = 0

x = 0

x = 0

x = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

29/x+1/(x^3) = 4/(x^2) // - 4/(x^2)

29/x-(4/(x^2))+1/(x^3) = 0

29/x-4*x^-2+1/(x^3) = 0

29*x^-1-4*x^-2+x^-3 = 0

t_1 = x^-1

1*t_1^3-4*t_1^2+29*t_1^1 = 0

t_1^3-4*t_1^2+29*t_1 = 0

t_1*(t_1^2-4*t_1+29) = 0

t_1^2-4*t_1+29 = 0

DELTA = (-4)^2-(1*4*29)

DELTA = -100

DELTA < 0

t_1 = 0

t_1 = 0

t_1 = 0

x^-1+0 = 0

x^-1 = 0

1*x^-1 = 0 // : 1

x^-1 = 0

x naleu017Cy do O

x belongs to the empty set

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